Quantization,

• Be covariant quantization of electromagnetic field (3) (Nakanishi - Lautrap theory)
  http://maldoror-ducasse.cocolog-nifty.com/blog/2009/06/3-lautrap-2191.html
  First, if μ=i, [a i (x 0, x), b (x 0, y)] With =0 [a i (x), b (y)]=-∫d 3 zd (y-z) [a i (x), ∂ z 0 b (z)]With you can write

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  Primeiramente, se μ=i, [um i (x 0, x), b (x 0, y)] com =0 [um i (x), zd do =-∫d 3 de b (y)] (y-z) [um i (x), ∂ z 0 b (z)] com você pode escrever
  
  
• Japanese weblog
  http://maldoror-ducasse.cocolog-nifty.com/blog/2010/04/propagator-theo.html
  First, δs'=. u + (XXINF) - ∫ - XXINF XXINF. u - + (t) [{∂/∂t+ (i/h c) h 1 (t)}u + (t)]dt-∫ - XXINF XXINF u - + (t) [{∂/∂t+ (i/h c) h 1 (t)}. u + (t)]dt you can write

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  Primeiramente, δs'=. u + (XXINF) - ∫ - XXINF XXINF. u - + (t) [{∂/∂t+ (i/h c) h 1 (t)} u + (t)] descolamento-∫ - XXINF XXINF u - + (t) [{∂/∂t+ (i/h c) h 1 (t)}. u + (t)] descolamento que você pode escrever
  
  
• weblog title
  http://maldoror-ducasse.cocolog-nifty.com/blog/2009/06/2-3e4f.html
  Furthermore, (□+m 2) Δ f (x) =-δ 4 (x) from, Δ f (x) fourier transform Δ f (x) ≡ (2π) -4 ∫d 4. If δ~ f (k) exp (- ikx) with you write, (k 2 - m 2) δ~ f (k) =1 it becomes

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  Além disso, (□+m 2) ” f de Î (x) =-δ 4 (x) de, ” f de Î (x) Fourier transforma o ” f de Î (x) ∫d -4 4. do ≡ (2π). Se δ~ f (k) o exp (- ikx) com você escreve, (k 2 - m 2) o δ~ f (k) =1 se torna