Quantization,

• Be covariant quantization of electromagnetic field (3) (Nakanishi - Lautrap theory)
  http://maldoror-ducasse.cocolog-nifty.com/blog/2009/06/3-lautrap-2191.html
  Then [a i (x 0, x), ∂ 0 b (x 0, y)]=-i∂ y i Δ 3 (x - y) you obtain

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  После этого [I (x 0, x), ∂ 0 b (x 0, y)]” 3 =-i∂ y i Î (x - y) вы получаете
  
  
• Japanese weblog
  http://maldoror-ducasse.cocolog-nifty.com/blog/2010/04/propagator-theo.html
  Therefore s= 1- (the i/h c) ∫ - XXINF XXINF h 1 (t) u + (t) dt and s -1 =1+ (the i/h c) ∫ - XXINF XXINF h 1 (t) u - (t) it is dt

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  Поэтому s= 1 - (i/h c) ∫ - XXINF XXINF h 1 (t) u + (t) ∫ dt и s -1 =1+ (i/h c) - XXINF XXINF h 1 (t) u - (t) dt
  
  
• weblog title
  http://maldoror-ducasse.cocolog-nifty.com/blog/2009/06/2-3e4f.html
  Then, commutation relation 4 dimensional [b (x), b (y)]B (x) =∫d 3 z {∂ z 0 d (x-z) b (z) - d (x-z) ∂ z 0 b (z)}It substituted [b (x), b (y)]=∫d 3 z {∂ z 0 d (x-z) [b (z), b (y)]- d (x-z) [∂ z 0 b (z), b (y)]Because} in the indication which becomes, z 0 of the right-hand side it is good with anything, z 0 =y 0 you put in place

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  После этого, соотношение коммутативности 4 габаритное [b (x), b (y)]=∫d 3 z b (x) {∂ z 0 d (x-z) b (z) - ∂ z 0 b d (x-z) (z)}Он заменил [b (x), b (y)]=∫d 3 z {∂ z 0 d (x-z) [b (z), b (y)]- d (x-z) [∂ z 0 b (z), b (y)]Потому что} в индикации которая становит, z 0 right-hand стороны хорошо с что-нибыдь, z 0 =y 0 вы положили в место